Solve the equation -6+3×=-9

Answers

Answer 1
Answer: -6 + 3x = -9

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And 6 to both sides:
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3x = -3

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Divide by 3 on both sides:
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x = -1

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Answer: x = -1
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both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. how high would this water rise if it were poured into the empty wide cylinder

Answers

The height of the water when poured into the empty wide cylinder is;

Option A; To the 7¹/₃ mark

Formula for volume of a cylinder is;

V = πr²h

where;

r is radius

h is height

We are told that water is poured into the wide cylinder up to the 4th mark. Thus, for the wide cylinder, h = 4. Thus;

V_wide = 4πR²

Similarly, we are told that water is poured into the narrow cylinder up to the 6th mark. Thus, for the narrow cylinder, h = 6. Thus;

V_narrow = 6πr²

Now, the volume of the water will be the same since it was the same quantity that was poured. Thus;

V_wide = V_narrow

4πR² = 6πr²

⇒ R²/r² = 6/4

simplifies to get; R²/r² = ³/₂

Now both cylinder were emptied and water poured rises to the 11th mark for the narrow cylinder. Thus;

πR²H = 11πr²

R²/r² = 11/H

Earlier, we saw that R²/r² = ³/₂. Thus;

11/H = ³/₂

H = 22/3

H =  7¹/₃

The complete question is;

Attached are the drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?

A) To the 7¹/₃ mark

B)To the 8th mark

C) To the 7¹/₂mark

D)To the 9th mark

E) To the 11th mark  

Read more at; brainly.com/question/16760517

Answer:

COMPLETE QUESTION:

To the right are drawings of a wide and a narrow cylinder. The cylinders have equally spaced marks on them. Water is poured into the wide cylinder up to the 4th mark (see A). This water rises to the 6th mark when poured into the narrow cylinder (see B). Both cylinders are emptied, and water is poured into the narrow cylinder up to the 11th mark. How high would this water rise if it were poured into the empty wide cylinder?

a)To the 7 1/2 mark b)To the 9th mark c)To the 8th mark d)To the 7 1/3 mark

e)To the 11th mark

ANSWER : Option D (To the 7 1/3 mark)

Step-by-step explanation:

First part of the question enables us to get the relationship between the radius of the wider cylinder (R) and the narrow cylinder(r) i.e

Volume of cylinders

π x R² x 4 = πxr²x 6

R²/r² = 6/4

after both cylinder were emptied

π x R² x h = π x r² x 11

R²/r² = 6/4 = 11/h

h = (4 x 11) /6 = 22/3 = 7 1/3 mark

Therefore, the height of the water in the wide cylinder is 7 1/3

WILL BE MARKED BRAINLYESTRay OJ bisects Angle LOK.

Measurement of Angle LOK = 82 degrees.

Solve for x.

Answers

Answer:

x = 14

Step-by-step explanation:

<LOJ = 3x

<KOJ = (2x + 12)°

<LOK = 82°

m<LOJ + m<KOJ = m<LOK (angle addition postulate)

3x + 2x + 12 = 82 (substitution)

5x + 12 = 82

5x = 82 - 12 (Subtraction property of equality)

5x = 70

x = 70/5 (division property of equality)

x = 14

Solve the equation x/4 - 7 = y for x

Answers

Answer:

x = 4y + 28

Step-by-step explanation:

x/4 - 7 = y

+7              +7

x/4 = y + 7

× 4             × 4

x = 4y + 28

Answer:

x = 4y + 28

Step-by-step explanation:

For this, you would need to simplify both sides of the equation, after isolating the variable.


The table gives the probability distribution of the annual rate of return on the stock of MNP Company, Inc. What is the expected value of the rate of return?

Answers

The expected value of the rate of return is 23.5%

What is Probability?

It is a branch of mathematics that deals with the occurrence of a random event.

Given is a table which gives the probabilitydistribution of the annual rate of return on the stock of MNP Company, Inc. We have to find out  the expected value of the rate of return

Let X be the return and p probability

Then

X     15%     20%    30%     35%  Total

p     0.2       0.4     0.3       0.1        1

x(p)  3           8        9          3.5     23.5

Hence Expected rate of return

E(x)= 23.5%

Hence, the expected value of the rate of return is 23.5%

To learn more on probability click:

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Do phone surveys provide adequate coverage of households with respect to one particular parameter? The parameter is the proportion of households without children. If telephone surveys provide adequate coverage of households, then p , the proportion of households without children in the set of all future samples reached by phone, must be equal to the proportion of households without children in the population of all households. Suppose that Thomas, a market analyst, contacts a simple random sample of 300 households as part of a national telephone survey. Of the households contacted, 129 households, or 43 %, have no children and 57 % have at least one child. The most recent census indicates that 48 % of all households have no children and 52 % have at least one child.

Answers

Complete  Question

The complete question is shown on the first uploaded image

Answer:

Based on the result of his test , Thomas should fail to reject null hypothesis at a significance level of  0.01. Thomas sufficient evidence  to conclude that  the proportion of  households without children in the set of all future samples reached by phone is not equal to the proportion of households without children in the population of all households.

Step-by-step explanation:

From the question we see that the p-value is greater than the level of significance (0.01 )so we fail to reject the null hypothesis.

This means that Thomas has  sufficient evidence to conclude that the proportion of households without children in the set of all future samples reached by phone is not equal to the proportion of households without children in the population of all households.

Complete the pattern 4,15,7,12,10,9 ? ? ? show me how you got your work

Answers

Given the pattern:
4,15,7,12,10,9,..
Every other term after the first term is increasing by 3. Thus continuing the pattern we shall have:
4, 15, 7, 12, 10, 9, 13, 11,16
thus the missing numbers will be:
13,11,16
Split this pattern into two sub-patterns.

We can see that odd position terms first, third, and fifth terms are increasing by 3.

We also can see that even position terms second, fourth, and sixth terms are decreasing by 3.

So the remaining term is seventh, eighth, and ninth terms. So from pattern above, seventh and ninth is continue after odd position term, so that would be 13 then 16.

eighth term is continue after even position term. That would be 6.

So then the remaining pattern would be 13, 6, 16.